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add a menu option for opening recent files, hard code some example xml files for testing

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This commit is contained in:
Huy Pham 2020-02-03 09:10:46 -08:00
parent 2c6307603a
commit ede9e93b52
2 changed files with 27 additions and 4 deletions
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11
daemon/core/gui/menuaction.py
View file

@ -89,12 +89,15 @@ class MenuAction:
title="Open",
filetypes=(("XML Files", "*.xml"), ("All Files", "*")),
)
if file_path:
self.app.core.xml_file = file_path
self.app.core.xml_dir = str(os.path.dirname(file_path))
self.open_xml_task(file_path)
def open_xml_task(self, filename):
if filename:
self.app.core.xml_file = filename
self.app.core.xml_dir = str(os.path.dirname(filename))
self.prompt_save_running_session()
self.app.statusbar.progress_bar.start(5)
task = BackgroundTask(self.app, self.app.core.open_xml, args=(file_path,))
task = BackgroundTask(self.app, self.app.core.open_xml, args=(filename,))
task.start()
def gui_preferences(self):

20
daemon/core/gui/menubar.py
View file

@ -1,3 +1,5 @@
import logging
import os
import tkinter as tk
from functools import partial
from typing import TYPE_CHECKING
@ -55,6 +57,17 @@ class Menubar(tk.Menu):
menu.add_command(label="Save", accelerator="Ctrl+S", command=self.save)
menu.add_command(label="Reload", underline=0, state=tk.DISABLED)
self.app.bind_all("<Control-s>", self.save)
sample_xmls = [
"sample1.xml",
"/home/ncs/.coretk/xmls/sample1.xml",
"sample1.xml",
]
recent = tk.Menu(menu)
for i in sample_xmls:
recent.add_command(label=i, command=partial(self.open_recent_files, i))
menu.add_cascade(label="Recent files", menu=recent)
# menu.add_command(label="Recent files")
menu.add_separator()
menu.add_command(label="Export Python script...", state=tk.DISABLED)
menu.add_command(label="Execute XML or Python script...", state=tk.DISABLED)
@ -409,6 +422,13 @@ class Menubar(tk.Menu):
menu.add_command(label="About", command=self.menuaction.show_about)
self.add_cascade(label="Help", menu=menu)
def open_recent_files(self, filename: str):
if os.path.isfile(filename):
logging.debug("Open recent file %s", filename)
self.menuaction.open_xml_task(filename)
else:
logging.warning("File does not exist %s", filename)
def save(self):
xml_file = self.app.core.xml_file
if xml_file: